化简求值：(x^2-16)/(x^2+8x+16)+x/(x-4)+1/(x^2-16),其中x=（根号下2）+1_数学解答

化简求值：(x^2-16)/(x^2+8x+16)+x/(x-4)+1/(x^2-16),其中x=（根号下2）+1

人气：312 ℃　时间：2020-06-21 16:05:49

解答

(x^2-16)/(x^2+8x+16)+x/(x-4)+1/(x^2-16)=(x+4)(x-4))/(x+4)^2+x/(x-4)+1/[(x+4)(x-4)]=(x-4))/(x+4)+x/(x-4)+1/[(x+4)(x-4)]=[(x-4)^2+x(x+4)+1]/[(x+4)(x-4)]=(2x^2-4x+17)/(x^2-16)=[2(x-1)^2+15]/(x^2-16)x=√2...