∫ dx/(2 + sin2x)= (1/2)∫ du/(2 + sinu),u = 2x= (1/2)∫ 1/[2 + 2y/(1 + y²)] · 2/(1 + y²) dy,y = tan(u/2),sinu = 2y/(1 + y²),du = 2dy/(1 + y²)= (1/2)∫ (1 + y²)/[(1 + y²...