已知数列{a n}是等差数列,Sn是其前n项和,求证:S5,S10-S5,S15-S10这三个数也成等差数列.
人气:478 ℃ 时间:2019-11-13 20:25:57
解答
s5=(a1+a5)*5/2=(a1+a1+4d)*5/2=5(a1+2d)=5a1+10ds10=(a1+a10)*10/2=(a1+a1+9d)*5/2=5(2a1+9d)=10a1+45ds15==(a1+a15)*15/2=(a1+a1+14d)*15/2=15(a1+7d)=15a1+105ds10-s5=10a1+45d-5a1-10d=5a1+35ds15-s10=15a1+105d...
推荐
- 已知数列{an}是等差数列,Sn是其前n项和,求证:S5,S10-S5,S15-S10这三个数也成等差数列
- 在等差数列{an}中,已知a1=20,前n项和为Sn,且S10=S15
- 设等比数列前n项和为Sn,公比为q.若S5,S15,S10成等差数列.求证
- 等差数列{an}中,S5=28,S10=36 (Sn为前n项和),则S15等于?
- 等差数列An的前n项和为Sn,已知S10=0 S15=25 求nSn的最小值为多少
- He ___(teach) you English well,doesn't he?
- 露西用英语怎么说?We can't put our bikes over there.改祈使句
- 闻一多(打一字)
猜你喜欢