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4x^2-28x+y^2+6y+58=0,求3x-2y.
人气:166 ℃ 时间:2020-01-27 22:00:47
解答
4x^2-28x+y^2+6y+58=0
4x^2-28x+49+y^2+6y+9=0
(2x-7)^2+(y+3)^2=0
(2x-7)^2=0,(y+3)^2=0
x=7/2
y=-3
3x-2y
=3*7/2-2*(-3)
=21/2+6
=33/2
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