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用洛必达法则求极限lim(x→0+)(1/x)∧tanx和lim(x→0)(x∧2×(e∧(1/x...
用洛必达法则求极限lim(x→0+)(1/x)∧tanx和lim(x→0)(x∧2×(e∧(1/x)∧2)),
人气:141 ℃ 时间:2019-10-20 19:50:48
解答
x->0+,lim(1/X)^tanx=lim(1+(1-x)/x)^tanx=lim(1+(1-x)/x)^(x/(1-x)*(1-x)/x*tanx)=lim e^((1-x)/x*tanx)=e^(lim(1-x)/x*tanx)=e^(lim(1-x))=e^1=ex->0,设y=1/x->∞,不太清楚你表达式中e^(1/x)^2的具体形式,lim e^(y...
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