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不论X,Y取何值代数式(X^3Y+3X^2Y-5XY^2+6Y^3)+(Y^3+2XY^2+X^2Y-2X^3)-(4X^2Y-X^3-3XY^2+7Y^3)的值是常数
人气:471 ℃ 时间:2019-08-19 16:35:43
解答
(X^3+3X^2Y-5XY^2+6Y^3)+(Y^3+2XY^2+X^2Y-2X^3)-(4X^2Y-X^3-3XY^2+7Y^3)=X^3+3X^2Y-5XY^2+6Y^3+Y^3+2XY^2+X^2Y-2X^3-4X^2Y+X^3+3XY^2-7Y^3=(X^3-2X^3+X^3)+(3X^2Y+X^2Y-4X^2Y)+(-5XY^2+2XY^2+3XY^2)+(6Y^3+Y^3-7Y^3...
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