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log(9)(a)=log(15)(b)=log(25)(a+2b),求b比a的值
log(9)(a)=log(15)(b)=log(25)(a+2b),其中9,15和25是底数
人气:246 ℃ 时间:2020-06-05 19:43:32
解答
log(9)(a)=1/log(a)(9)=1/2{log(a)(3)}
log(9)(a)=log(15)(b)=log(25)(a+2b)=k
9^k=a,15^k=b
a+2b=25^k
9^k+2*15^k=25^k
(3/5)^k+2=(5/3)^k
(3/5)^k=y,(5/3)^k=1/y
y^2+2y+1=2
y=根号2-1或y=1-根号2(<0)舍去
(3/5)k=根号2-1
k(lg3-lg5)=lg(根号2-1)
k=lg(根号2-1)/(lg3-lg5)....
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