> 数学 >
sin(a+b)cos(a-b)=1/5;则(cosa)^2-(sinb)^2=
人气:331 ℃ 时间:2019-11-02 12:14:39
解答
1/5.
cos(a+b)cos(a-b)
=(cosacosb-sinasinb)(cosacosb+sinasinb)
=(cosacosb)^2-(sinasinb)^2
=cosa^2[1-(sinb)^2]-sinb^2[1-(cosa)^2]
=(cosa)^2-(sinb)^2
=1/5
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版