量子力学矩阵A,B,C满足A^2=B^2=C^2=1,BC-CB=iA,证明AB+BA=AC+CA=0
人气：492 ℃ 时间：2020-03-09 16:26:05
解答
BC-CB=iA,
两边左乘B得 BBC-BCB=C-BCB=iBA
两边右乘B得 BCB-CBB=BCB-C=iAB
两式相加得AB+BA=0
后一个同理
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