a、b是方程x²-2mx+m+6=0的两个实数根∴a+b=2mab=m+6（a-1）²+（b-1）²=a²-2a+1+b²-2b+1=a²+2ab+b²-2ab-2(a+b)+2=(a+b)²-2ab-2(a+b)+2=4m²-2m-12-4m+2=4m²-6m-10...