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∫[(3x+1)/(4+x^2)^(1/2)]dx ∫1/[(x^2)(4-x^2)]dx
人气:491 ℃ 时间:2020-06-08 09:00:40
解答
(1)原式=∫[3x/(4+x^2)^(1/2)]dx+∫dx/(4+x^2)^(1/2)=3/2*∫d(4+x^2)/(4+x^2)^(1/2)+ln[x+(4+x^2)^(1/2)]+C=3(4+x^2)^(1/2)+ln[x+(4+x^2)^(1/2)]+C(2)原式=1/4*∫[1/x^2+1/(4-x^2)]dx=1/4*[∫dx/x^2+∫dx/(4-x^2)]...
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