设
f1(x)＝，定义f
n+1（x）=f
1[f
n（x）]，
an＝，其中n∈N
*，则数列{a
n}的通项______．
人气：445 ℃ 时间：2019-09-17 16:50:47
解答
（1）∵f1（0）=2，a1=2−12+2=14，fn+1（0）=f1[fn（0）]=21+fn(0)，∴an+1=fn+1(0)−1fn+1(0)+2=21+fn(0)−121+fn(0)+2=1−fn(0)4+2fn(0)=-12•fn(0)−1fn(0)+2=-12an，∴q=an+1an=-12，∴数列{an}是首项为14，公...
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