貌似你漏打字了.应该是log2真数是a[1],a[2],…a[2n-1].答案是C∵a[n]是等比数列.又有a[5]*a[2n-5]=2^2n ∴a[1]*a[2n-1]=2^2n设a[n]得公比为q.∵a[1]*q^n-1=a[n],a[2n-1]=a[1]*q^2n-2,∴a[1]*a[2n-1]=(a[1]*q*n-1)&su...