Sn=a1*n+0.5*n*(n-1)d;
Sn=0.5*d*n^2+(a1-0.5*d)*n=p*n^2+(p+1)*n+p+3
因此,
0.5*d=p;
a1-0.5*d=p+1;
p+3=0;
解得：
p=-3;
d=-6;
a1=-5.