用MATLAB图解法求方程y/(x^2+y^2+1)=sin(x+cos(y))最靠近原点的解,请大家帮帮小弟的忙!
人气:434 ℃ 时间:2020-03-29 14:01:20
解答
syms x yf=y/(x^2+y^2+1)-sin(x+cos(y))ezplot(f,[-2 2],[-2 2])h=get(gca,'Children');x=get(h,'xdata');y=get(h,'ydata');c=x.^2+y^2;%解离原点距离n=find(c==min(c));%找最短x(n)%结果y(n)
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