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数学
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求证:1+sin2a/cos2a=tan(π/4+x)
人气:372 ℃ 时间:2020-05-09 18:57:00
解答
1+sin2a/cos2a=(sin^2a+2sinacosa+cos^2a)/(cos^2a-sin^2a)=(cosa+sina)^2/(cosa+sina)(cosa-sina)=(cosa+sina)/(cosa-sina)=(1+tana)/(1-tana)=(tanπ/4+tana+)/(1-tanπ/4*tana)=tan(π/4+x)
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