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求证(1+sin2a-cos2a)/(1+sin2a+cos2a)=tan a
人气:392 ℃ 时间:2020-05-04 02:52:26
解答
(1+sin2a-cos2a)/(1+sin2a+cos2a)
=[1+2sinacosa-(cosa)^2+(sina)^2]/[1+2sinacosa+(cosa)^2-(sina)^2]
=[2(sina)^2+2sinacosa]/[2(cosa)^2+2sinacosa]
=[2sina(sina+cosa)]/[2cosa(sina+cosa)]
=sina/cosa
=tana
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