已知sina-cosa=sinacosa,则sin2a的值为?答案是2倍的根2-2,
人气:449 ℃ 时间:2020-04-09 09:30:28
解答
两边平方
sin²a+cos²a-2sinxcosa=(sinxcosa)²
(sinacosa)²+2sinxcosa-1=0
sinacosa=-1±√2
2sinxcosa=-2±2√2
sin2a=-2±2√2
-1<=sin2a<=1
所以sin2a=-2+2√2
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