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-1/2+1/4-1/8+1/16-1/32+1/64-.+1/1024=?
人气:142 ℃ 时间:2019-12-13 17:16:59
解答
设原式= A
则:
A= -1/2+1/4-1/8+1/16-1/32+1/64-.+1/1024
2A= -1+1/2-1/4+1/8-1/16+1/32-1/64+.+1/512
两式相加,中间各项正负相消,得:
3A= -1+1/1024= -1023/1024
所以:
A= -341/1024
即:
-1/2+1/4-1/8+1/16-1/32+1/64-.+1/1024= -341/1024
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1/2+1/4+1/8+1/16+1/32+1/64+1/128+.+1/1024
1+2+4+8+16+32+64.+1024+2056+4112
1/2+1/4+1/8+1/16+1/32+1/64+.+1024=?
1+2+4+8+16+32+64+128+256+512+1024=_.
1024+512+256+128+64+32+16+8+4+2+1求解
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