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解不等式:(x²-4x+1)/(3x²-7x+2)≥1
人气:356 ℃ 时间:2020-05-13 14:45:24
解答
(x^2-4x+1)/(3x^2-7x+2)≥1
x^2-4x+1≥3x^2-7x+2
0≥2x^2-3x+1
0≥(2x-1)(x-1)
1≥x≥1/2
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