求下列函数的值域:(1)Y=(5X-1)/(4X+2);(2)Y=(X²-4x+3)/(2X²-X-1)_数学解答

求下列函数的值域:(1)Y=(5X-1)/(4X+2);(2)Y=(X²-4x+3)/(2X²-X-1)

人气：104 ℃　时间：2019-10-10 05:39:16

解答

(1)Y=(5X-1)/(4X+2)= 5/4(X-1/5)/(X+1/2)= 5/4(X+1/2-7/10)/(X+1/2)= 5/4 - (7/8)/(X+1/2)- (7/8)/(X+1/2)≠05/4 - (7/8)/(X+1/2)≠5/4值域（-∞,5/4）,（5/4,+∞）(2)Y=(X²-4x+3)/(2X²-X-1)= (X-1)(X-3)/...太感谢了