设该数列为{a_n}，
n为偶数，a₁•a_n=a₂•a_n-1=a₃•a_n-2=…=a

n

2

•a

n

2

+1
∴中间n个数的积为(

n+1

n

)

n

2

当n为奇数，a₁•a_n=a₂•a_n-1=a₃•a_n-2=…=（a

n+1

2

）²•
中间n个数的积为
(

n+1

n

) 

n−1

2

×(

n+1

n

) 

1

2

=(

n+1

n

)

n

2

综上所述，结果为(

n+1

n

)

n

2

故答案为(

n+1

n

)

n

2