设该数列为{an}，n为偶数，a1•an=a2•an-1=a3•an-2=…=an2•an2+1∴中间n个数的积为(n+1n)n2当n为奇数，a1•an=a2•an-1=a3•an-2=…=（an+12）2•中间n个数的积为(n+1n) n−12×(n+1n) 12=(n+1n)n2综上...