原式=[(x+3)(x-2)/(x-3)]÷[(x+3)/(x-3)(x+2)]
=[(x+3)(x-2)/(x-3)]×[(x-3)(x+2)/(x+3)]
=[(x+3)(x-2)(x-3)(x+2)/[(x-3)(x+3)]
=(x-2)(x+2)
=x²-4