f(x)=√3sin^2 x+sinxcosx-(√3/2)（x∈R）=√3*[(1-cos2x)/2]+(1/2)sin2x-(√3/2)=(√3/2)-(√3/2)cos2x+(1/2)sin2x-(√3/2)=(1/2)sin2x-(√3/2)cos2x=sin[2x-(π/3)](1)f(π/4)=sin[(π/2)-(π/3)]=sin(π/6)=1/2(...