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已知tan(π/4+A)=1/5,求 (sin2A-sin^A)/(1-COS2a)的值
人气:246 ℃ 时间:2020-05-16 16:36:09
解答
令B = π / 4.-> tan(A + B) = (tanA - tanB )/(1+ tanA tanB) = 1 / 5 ->( tanA - 1 )/ (1+ tan A) =1 / 5-> tan A = 3 / 2.(sin2A-sin^2A)/(1-COS2a) =( 2cosA sin A - sin^2(A) ) / ( 1 - (1 - 2sin^2(A) ) ) = ...
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