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数学
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若对于任意实数x,等式(2x-1)⒉-a(x+b)⒉=px都成立,(a.b.c为常数),求p的值?
人气:275 ℃ 时间:2020-10-01 19:09:10
解答
展开,按照x的降幂次排列,令x前面的系数等于0,就能得到结果!
由此有:
(4-a)x^2-(4+2ab+p)x=ab^2-1,
令
4-a=0
ab^2-1=0
(4+2ab+p)=0
解之就能得到结果!
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