已知A+C=2B则A+C+B=3B=180° B=60°若边AB上的高CH=4倍根号3则BC=CH/sinB=4√3/sin60°=8因tanB=-tan(A+C)=-(tanA+tanC)/(1-tanAtanC)tanAtanC=2+√3 (1)所以tan60°=-(tanA+tanC)/(1-2-√3)tanA+tanC=3+√3 (2)设C>...