f(x)=1-[2/(x-2)] x属于D的值域为(-无穷,-3)U(1,2),其定义域为?_数学解答

f(x)=1-[2/(x-2)] x属于D的值域为(-无穷,-3)U(1,2),其定义域为?

人气：217 ℃　时间：2020-09-24 23:14:24

解答

1-2/(x-2)<-3
2/(x-3)>4
0<(x-3)/2<1/4
031<1-2/(x-2)<2
-1<2/(x-2)<0
所以(x-2)/2<-1
x-2<-2
x<0
所以定义域(-无穷,0)∪(3,7/2)