因为：x^2+x+1=x^2+2*1/2*x+(1/2)^2+1-(1/2)^2=(x+1/2)^2+3/4＞0 则,原式：(3x^2+2x+2)/(x^2+x+1)≥m 变形为,(3x^2+2x+2)≥m*(x^2+x+1)=mx^2+mx+m 整理得,(3-m)x^2+(2-m)x+(2-m)≥0 ① 当,3-m=0 即,m=3时,原式=(3-3)...