f(x)=1/[(x+1)In(x+1)]的导函数是什么?_数学解答

f(x)=1/[(x+1)In(x+1)]的导函数是什么?

人气：202 ℃　时间：2020-05-21 09:15:57

解答

f'(x)={[1/(x+1)][1/ln(x+1)]}'=[1/(x+1)]'[1/ln(x+1)]+[1/(x+1)][1/ln(x+1)]'=-1/[(x+1)²ln(x+1)]+[1/(x+1)][-1/ln²(x+1)][1/(x+1)]=-1/[(x+1)²ln(x+1)]-1/[(x+1)²ln²(x+1)]=-[ln(x+1)+1]...