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因式分解3题、6y^4+19^2+10,6(a+b)^2+a+b-35,7(x-1)^2+4(x-1)(y+2)-20(y+2)^2
人气:367 ℃ 时间:2020-05-19 05:49:37
解答
6y^4+19^2+10,=(3y^2+2)(2y^2+5)6(a+b)^2+a+b-35,=[3(a+b)-7][2(a+b)+5]=(3a+3b-7)(2a+2b+5)7(x-1)^2+4(x-1)(y+2)-20(y+2)^2=[7(x-1)-10(y+2)][(x-1)+2(y+2)]=(7x-7-10y-20)(x-1+2y+4)=(7x-10y-27)(x+2y+3)
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