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证明不等式1/log5(19)+2/log3(19)+3/log2(19)
人气:306 ℃ 时间:2020-03-27 23:04:54
解答
1/log5(19)+2/log3(19)+3/log2(19)=log19(5)+log19(3^2)+log19(2^3)=log19(5*9*8)=log19(360)
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