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计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15
人气:494 ℃ 时间:2019-12-01 14:27:44
解答
log2 6-log2 3=log2 (6÷3)=log2 2=1,
lg5+lg2=lg(5×2)=lg10=1,
log5 3+log5 1/3=log5 (3×1/3)=log5 1=0,
log3 5-log3 15=log3 (5÷15)=log 3 (1/3)=-1
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