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若函数fx=cosπx/3,(x属于整数)则f(0)+f(1)+f(2)+.f(2009)=
人气:438 ℃ 时间:2020-07-03 21:36:11
解答
∵f(x)=cos(xπ/3)∴f(0)=1f(1)=cosπ/3=1/2f(2)=cos2π/3=cos(π/2-π/6)=-sin(π/6)=-1/2f(3)=cosπ=-1f(4)=cos(4π/3)=cos(π+π/3)=-cosπ/3=-1/2f(5)=cos5π/3=cos(2π-π/3)=cosπ/3=1/2……f(2009)=cos2009π...
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