∫dx/[(sinx/2)+cos(x/2)]=∫[cos(x/2)-sin(x/2)]dx/[cos(x/2)^2-sin(x/2)^2]=∫cos(x/2)dx/cosx-∫sin(x/2)dx/cosx=2∫dsin(x/2)/[1-2sin(x/2)^2] + 2∫dcos(x/2)/[2(cosx/2)^2-1]=∫d(sinx/2)/(1-√2sin(x/2)) +∫...