1.已知x-3y=0,且xy≠0,求x²-y²/x²-xy+y²的值.3.当x取何值时,分_数学解答

1.已知x-3y=0,且xy≠0,求x²-y²/x²-xy+y²的值.
3.当x取何值时,分式(1+2x)(1/2-x)/(2x-1)²的值为零.
2.已知a/b=2,求a²-4ab+3b²/a²-8ab+7b²的值.

人气：259 ℃　时间：2020-03-30 06:24:34

解答

1.已知x-3y=0,且xy≠0,求x²-y²/x²-xy+y²的值x-3y=0x=3y(x²-y²)/(x²-xy+y²)=(9y²-y²)/(9y²-3y²+y²)=8/73.当x取何值时,分式(1+2x)(1/2-x)/(2x-1)&#...