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数学
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1-1×2分之1+2×3分之1+…+50×51分之1
人气:297 ℃ 时间:2020-03-22 17:51:29
解答
1-1×2分之1+2×3分之1+…+50×51分之1
=1/(1*2)+1/(2*3)+.+1/(50*51)
=(1-1/2)+(1/2-1/3)+.+(1/50-1/51)
=1-1/51
=50/51
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1*2+2*3+3*4+……+50*51
设1/2+1/3+...+1/50为x,(1/2+1/3+...+1/50)(1+1/2+1/3+...+1/50)-(1+1/2+1/3+...+1/50)(1/2+1/3+...+1/50+1/51)
1*1/2+1+2*1/3+2+3*1/4+3+.+50*1/51+50=?
1+2+3+.
(1×2/1)+1+(2×3/1)+2+(3×4/1)+3+……+(50×51/1)+50要讲解的!
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