sinx/2+cosx=1
sinx/2=1-cosx=2sin²x/2
2sin²x/2-sinx/2=0
sinx/2（2sinx/2-1）=0
解得
sinx/2=0x/2=kπx=2kπ
2sinx/2-1=0 sinx/2=1/2
x/2=2kπ+π/6或x/2=2kπ+5π/6
x=4kπ+π/3或x=4kπ+5π/3
所以方程的解是：
x1=2kπ
x2=4kπ+π/3
x3=4kπ+5π/3