已知x和y满足x²+4y²=2x+4y-2,求3次根号x-2y的值
人气：145 ℃ 时间：2019-10-10 05:45:59
解答
x²+4y²=2x+4y-2
x²-2x+1+4y²-4y+1=0
(x-1)^2+(2y-1)^2=0
x-1=0 x=1
2y-1=0 y=1/2
(x-2y)^(1/3)
=(1-1)^(1/3)
=0
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