已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y已知2x-y=10,求[(x_数学解答

已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y就是已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y/4y就是除以4y

人气：310 ℃　时间：2019-09-17 02:39:24

解答

先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y [(x²+y²)-(x-y)²+2y(x-y)]/4y =[x²+y²-(x²+y²-2xy)+2xy-2y²]/4y=[x²+y²-x²-y²+2xy+2xy-2y²]/...