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(2sin2α/1+cos2α)*(cosα)^2/cos2α=?
人气:287 ℃ 时间:2020-05-09 15:34:10
解答
(2sin2α/1+cos2α)*(cosα)^2/cos2α
=2tana*(cosα)^2/cos2α
=2tana*(cosα)^2/cos2α
=2sinα*cosα/cos2α
=sin2α/cos2α
=tan2a
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