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已知tanΘ=1/3,求cos2Θ+2sin2Θ
人气:294 ℃ 时间:2020-05-10 17:25:23
解答
因为 tan Θ =1/3,所以 cos 2Θ +2 sin 2Θ = [ (cos Θ)^2 -(sin Θ)^2 +4 sin Θ cos Θ ] / [ (sin Θ)^2 +(cos Θ)^2 ]= [ 1 -(tan Θ)^2 +4 tan Θ ] / [ (tan Θ)^2 +1 ]= [ 1 -(1/3)^2 +4 *(1/3) ] / [ (1/3)...
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