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(2sin2α/1+cos2α)*(cosα)^2/cos2α=多少
人气:498 ℃ 时间:2020-05-10 17:23:52
解答
(2sin2α/1+cos2α)*(cosα)^2/cos2α
=(2sin2α)/(2cos²α) *(cos²α)/(cos2α)
=sin2α/cos2α
=tan2α
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