解
[3/(x-1)-(x-1)]÷(x²-4x+4)/(x-1)
=[3/(x-1)-(x-1)]×(x-1)/(x-2)²
=3/(x-2)²-(x-1)²/(x-2)²
=[3-(x-1)²]/(x-2)²
=(3-x²+2x-1)/(x-2)²
=(-x²+2x+2)/(x-2)²
=(-1-2+2)/(-3)²
=-1/9