√(5x-6)-√(2x-3)=√(3x-5)√(5x-6)=√(2x-3)+√(3x-5)5x-6=2x-3+3x-5+2√[(2x-3)(3x-5)]5x-6=5x-8+2√[(2x-3)(3x-5)]1=√[(2x-3)(3x-5)](2x-3)(3x-5)=16x^2-19x+14=0(x-2)(6x-7)=0x=2,或x=7/6而2x-3≥0,即x≥3/2所...