你好!设 (x+2y)/3 = (y+3z)/4 = (z+5x)/5 = k则 x+2y = 3k y+3z = 4kz+5x = 5k解方程组得x=25k/31y=34k/31z=30k/31故x：y：z=25：34：30已经验算过了,绝对正确!还可以这么做x+2y = 3k ①y+3z = 4k ②z+5x = 5k ③① ...