> 数学 >
求定积分∫(π/2,-π/2) 根号cos^x-cos^4x dx
∫(π/2,-π/2) 根号cos^2x-cos^4x dx
人气:154 ℃ 时间:2019-12-12 23:53:18
解答
∫(π/2,-π/2) √(cos^2 x-cos^4 x) dx
=∫(π/2,-π/2) √[cos^2 x(1-cos^2 x)] dx
=∫(π/2,-π/2) √[cos^2 x *sin^2 x] dx
=∫(π/2,-π/2) cosx*sinx dx
=∫(π/2,-π/2) sinx d(sinx)
= (1/2)(sinx)^2 |(π/2,-π/2)
= (1/2)(1-1)
=0
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版