y=-√3sin2x/2+cos2x/2+√3sin2x=cos(π/6)*sin2x+sin(π/6)*cos2x=sin(2x+π/6)
sinx的递增区间是[-π/2+2kπ,π/2+2kπ],所以sin(2x+π/6)的递增区间是[-π/3+2kπ,π/6+2kπ]