(1)a3^2=9a2a6 (a2p)^2=9a2(a2p^4) a2^2p^2=9a2^2p^4 ∵此数列各项均为正数∴a2^20,p>0 两边同时除以a2^2p^2,得9p^2=1,p=1/3 2a1+3a2=1 2a1+3*[(1/3)*a1]=1 2a1+a1=1 3a1=1 a1=1/3 an=a1p^(n-1)=1/3*(1/3)^(n-1)=1/3...